b^(1/9)=2

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Solution for b^(1/9)=2 equation:


b in (-oo:+oo)

b^(1/9) = 2 // - 2

b^(1/9)-2 = 0

1*b^(1/9) = 2 // : 1

b^(1/9) = 2

b^(1/9) = 2 // ^ 9

b = 512

b = 512

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